162=-16t^2+150t

Solution for 162=-16t^2+150t equation:

162=-16t^2+150t

We move all terms to the left:

162-(-16t^2+150t)=0

We get rid of parentheses

16t^2-150t+162=0

a = 16; b = -150; c = +162;
Δ = b2-4ac
Δ = -1502-4·16·162
Δ = 12132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12132}=\sqrt{36*337}=\sqrt{36}*\sqrt{337}=6\sqrt{337}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-6\sqrt{337}}{2*16}=\frac{150-6\sqrt{337}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+6\sqrt{337}}{2*16}=\frac{150+6\sqrt{337}}{32}
$